Check Overlapping Sequences

Write a Python function `overlapping` that checks whether any value in one sequence exists in another sequence. The function should take two sequences as input and return `True` if there is at least one common element between them, otherwise return `False`.

#### Example Usage
```python [main.nopy]
print(overlapping([1, 2, 3, 4, 5], [6, 7, 8, 9]))  # Output: False
print(overlapping([1, 2, 3], [3, 4, 5]))          # Output: True
print(overlapping(['a', 'b'], ['c', 'd', 'a']))   # Output: True
```

#### Requirements
- The function should work for sequences of any type (e.g., lists, tuples).
- The function should return a boolean value.
- Avoid using built-in set operations for this challenge.
def overlapping(seq1, seq2):
    """
    Check if any value in seq1 exists in seq2.

    Args:
        seq1: The first sequence.
        seq2: The second sequence.

    Returns:
        bool: True if any value in seq1 exists in seq2, otherwise False.
    """
    # Implement the logic to check for overlapping elements
    pass
Intermediate functionsloopsconditionals
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