N = int(input("Введите натуральное число: "))
count = 0

while N > 0:
    count += 1
    N //= 10

print(count)
The provided code counts the number of digits in a natural number `N`. Here’s the complete code with a brief explanation:
Python
N = int(input("Введите натуральное число: "))  # Input a natural number
count = 0

while N > 0:
    count += 1  # Increment count for each digit
    N //= 10    # Remove the last digit

print(count)  # Output the number of digits
2

This code will prompt the user to enter a natural number and then print the count of its digits.