Count Identical Items in Three Lists

Write a Python function `count_samepair(list1, list2, list3)` that takes three lists of equal length as input and returns the count of items that are identical and in the same position across all three lists.

#### Example Usage
```python [main.nopy]
print(count_samepair([1, 2, 3], [1, 2, 4], [1, 2, 3]))  # Output: 2
print(count_samepair([1, 2, 3], [4, 5, 6], [7, 8, 9]))  # Output: 0
print(count_samepair([1, 2, 3], [1, 2, 3], [1, 2, 3]))  # Output: 3
```

#### Constraints
- The input lists will always have the same length.
- The lists can contain any hashable elements.
def count_samepair(list1, list2, list3):
    """
    Count the number of items that are identical and in the same position across three lists.

    Args:
        list1 (list): The first list.
        list2 (list): The second list.
        list3 (list): The third list.

    Returns:
        int: The count of identical items in the same position.
    """
    # Initialize the result counter
    result = 0
    # Iterate through the lists and compare items
    # Placeholder for the solution
    return result
Intermediate listsloopszip
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