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Create a dictionary where the values are the squares of the original values

Question:
Write a function called square_dict_values that takes a dictionary as input and returns a new dictionary where the values are the squares of the original values. Use dictionary comprehension to create the new dictionary.

Example:
Input: {"a": 2, "b": 3, "c": 4}
Output: {"a": 4, "b": 9, "c": 16}

def square_dict_values(dictionary):
    """
    Creates a new dictionary where the values are the squares of the original values.

    Args:
    dictionary (dict): The input dictionary.

    Returns:
    dict: A new dictionary with the squared values.
    """
    # TODO: Implement the square_dict_values function
    pass