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Write a Python function `max_occurrences(nums)` that takes a list of integers `nums` and returns the integer that appears most frequently in the list. If there is a tie, return any one of the most frequent integers. If the list is empty, return `None`. #### Example Usage ```python [main.nopy] print(max_occurrences([2, 3, 8, 4, 7, 9, 8, 2, 6, 5, 1, 6, 1, 2, 3, 2, 4, 6, 9, 1, 2])) # Output: 2 print(max_occurrences([10, 20, 20, 30, 40, 90, 80, 50, 30, 20, 50, 10])) # Output: 20 print(max_occurrences([])) # Output: None ```
from collections import defaultdict
def max_occurrences(nums):
"""
Find the item with the maximum frequency in the list.
Args:
nums (list): A list of integers.
Returns:
int: The integer with the highest frequency, or None if the list is empty.
"""
# Initialize a dictionary to count occurrences
frequency = defaultdict(int)
# Count the occurrences of each number
for num in nums:
frequency[num] += 1
# Placeholder for the solution
pass