Find Item with Maximum Frequency

Write a Python function `max_occurrences(nums)` that takes a list of integers `nums` and returns the integer that appears most frequently in the list. If there is a tie, return any one of the most frequent integers. If the list is empty, return `None`.

#### Example Usage
```python [main.nopy]
print(max_occurrences([2, 3, 8, 4, 7, 9, 8, 2, 6, 5, 1, 6, 1, 2, 3, 2, 4, 6, 9, 1, 2]))  # Output: 2
print(max_occurrences([10, 20, 20, 30, 40, 90, 80, 50, 30, 20, 50, 10]))  # Output: 20
print(max_occurrences([]))  # Output: None
```

from collections import defaultdict

def max_occurrences(nums):
    """
    Find the item with the maximum frequency in the list.

    Args:
        nums (list): A list of integers.

    Returns:
        int: The integer with the highest frequency, or None if the list is empty.
    """
    # Initialize a dictionary to count occurrences
    frequency = defaultdict(int)

    # Count the occurrences of each number
    for num in nums:
        frequency[num] += 1

    # Placeholder for the solution
    pass

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Intermediate lists

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