Remove Consecutive Duplicates

Write a Python function `consecutive_duplicates` that removes consecutive duplicate elements from a given list. The function should return a new list where only the first occurrence of each consecutive duplicate is retained.

#### Function Signature
```python [main.nopy]
def consecutive_duplicates(nums: list) -> list:
    pass
```

#### Example Usage
```python [main.nopy]
print(consecutive_duplicates([0, 0, 1, 2, 3, 4, 4, 5, 6, 6, 6, 7, 8, 9, 4, 4]))
# Output: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 4]

print(consecutive_duplicates(['a', 'a', 'b', 'c', 'd', 'd', 'a', 'a']))
# Output: ['a', 'b', 'c', 'd', 'a']
```

#### Constraints
- The input list can contain any hashable elements (e.g., integers, strings, etc.).
- The function should preserve the order of the elements in the input list.

from itertools import groupby

def consecutive_duplicates(nums: list) -> list:
    """
    Remove consecutive duplicate elements from the list.

    Args:
        nums (list): The input list containing elements.

    Returns:
        list: A new list with consecutive duplicates removed.
    """
    # Placeholder for the solution
    pass

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Intermediate lists loops

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