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Write a Python function `consecutive_duplicates` that removes consecutive duplicate elements from a given list. The function should return a new list where only the first occurrence of each consecutive duplicate is retained.
#### Function Signature
```python [main.nopy]
def consecutive_duplicates(nums: list) -> list:
pass
```
#### Example Usage
```python [main.nopy]
print(consecutive_duplicates([0, 0, 1, 2, 3, 4, 4, 5, 6, 6, 6, 7, 8, 9, 4, 4]))
# Output: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 4]
print(consecutive_duplicates(['a', 'a', 'b', 'c', 'd', 'd', 'a', 'a']))
# Output: ['a', 'b', 'c', 'd', 'a']
```
#### Constraints
- The input list can contain any hashable elements (e.g., integers, strings, etc.).
- The function should preserve the order of the elements in the input list.from itertools import groupby
def consecutive_duplicates(nums: list) -> list:
"""
Remove consecutive duplicate elements from the list.
Args:
nums (list): The input list containing elements.
Returns:
list: A new list with consecutive duplicates removed.
"""
# Placeholder for the solution
pass