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Rotate Left Bits

Write a Python function `left_rotate(n, d)` that rotates the bits of a 32-bit integer `n` to the left by `d` positions. The function should handle the wrap-around of bits correctly.

#### Example Usage
```python [main.nopy]
print(left_rotate(16, 2))  # Output: 64
print(left_rotate(10, 2))  # Output: 40
print(left_rotate(0b0001, 3))  # Output: 0b1000
```

#### Constraints
- Assume `n` is a 32-bit integer.
- `d` is a non-negative integer.
- The function should handle cases where `d` is greater than 32 by using modulo operation.
def left_rotate(n, d):
    """
    Rotate the bits of a 32-bit integer n to the left by d positions.

    Args:
    n (int): The number to rotate.
    d (int): The number of positions to rotate.

    Returns:
    int: The result of the left rotation.
    """
    # Define the number of bits in the integer
    INT_BITS = 32
    # Placeholder for the solution
    pass
Intermediate functions
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