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Find Second Smallest Number

Write a Python function `second_smallest(numbers)` that takes a list of numbers as input and returns the second smallest unique number in the list. If the list does not contain at least two unique numbers, the function should return `None`.

#### Example Usage
```python [main.nopy]
print(second_smallest([1, 2, -8, -2, 0, -2]))  # Output: -2
print(second_smallest([1, 1, -0.5, 0, 2, -2, -2]))  # Output: -0.5
print(second_smallest([2, 2]))  # Output: None
print(second_smallest([2, 2, 2]))  # Output: None
```

#### Constraints
- The input list can contain integers and floating-point numbers.
- The input list can have duplicate values.
- The function should handle edge cases, such as an empty list or a list with only one unique number.
def second_smallest(numbers):
    """
    Find the second smallest unique number in a list.

    Args:
        numbers (list): A list of numbers (integers or floats).

    Returns:
        float or int or None: The second smallest unique number, or None if not applicable.
    """
    # Remove duplicates and sort the list
    # Check if there are at least two unique numbers
    # Return the second smallest unique number or None
    pass
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