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Sum Non-Repeated Elements

Write a Python function `sum_non_repeated_elements` that takes a list of integers as input and returns the sum of all elements that appear only once in the list.

#### Example Usage
```python [main.nopy]
print(sum_non_repeated_elements([1, 2, 2, 3, 4, 4, 5]))  # Output: 9 (1 + 3 + 5)
print(sum_non_repeated_elements([10, 20, 10, 30, 40]))  # Output: 90 (20 + 30 + 40)
print(sum_non_repeated_elements([1, 1, 1, 1]))          # Output: 0 (no unique elements)
```

#### Constraints
- The input list will contain integers.
- The list can be empty, in which case the function should return `0`.
def sum_non_repeated_elements(nums):
    """
    Calculate the sum of all non-repeated elements in the list.

    Args:
    nums (list): A list of integers.

    Returns:
    int: The sum of all non-repeated elements.
    """
    # Placeholder for the implementation
    pass
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