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Write a Python function `count_char_position` that takes a string as input and returns the count of characters in the string that occur at the same position in the string as in the English alphabet. The comparison should be case-insensitive.
For example:
- The character 'A' (or 'a') is at position 0 in the alphabet.
- The character 'B' (or 'b') is at position 1 in the alphabet.
#### Example Usage
```python [main.nopy]
print(count_char_position("xbcefg")) # Output: 2
print(count_char_position("ABcED")) # Output: 3
print(count_char_position("AbgdeF")) # Output: 5
```
#### Constraints
- The input string will only contain alphabetic characters.
- The function should be case-insensitive.def count_char_position(input_string):
"""
Count the number of characters in the string that occur at the same position
in the string as in the English alphabet (case insensitive).
Args:
input_string (str): The input string to evaluate.
Returns:
int: The count of characters matching the condition.
"""
# Initialize the count variable
count = 0
# Iterate through the string and check the condition
for i, char in enumerate(input_string):
# Placeholder for the condition to check
pass
# Return the final count
return count