Count Characters with Vowel Neighbors

Write a Python function `count_vowel_neighbors(s: str) -> int` that takes a string `s` as input and returns the count of characters in the string that have vowels as their neighbors. A vowel is defined as one of the characters `a`, `e`, `i`, `o`, `u` (case-insensitive).

#### Rules:
1. Only consider lowercase and uppercase English alphabets.
2. Characters at the beginning or end of the string are considered to have a neighbor only on one side.

#### Example Usage:
```python [main.nopy]
count_vowel_neighbors("bestinstareels")  # Output: 7
count_vowel_neighbors("amazonprime")  # Output: 5
count_vowel_neighbors("partofthejourneyistheend")  # Output: 12
```
def count_vowel_neighbors(s: str) -> int:
    """
    Count characters in the string that have vowels as their neighbors.

    Args:
        s (str): The input string.

    Returns:
        int: The count of characters with vowels as neighbors.
    """
    # Define the set of vowels
    vowels = {'a', 'e', 'i', 'o', 'u'}
    count = 0

    # Iterate through the string to check neighbors
    for i in range(len(s)):
        # Placeholder for logic to check neighbors
        pass

    return count
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