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Write a Python function `diff_even_odd(numbers)` that takes a list of integers as input and returns the difference between the first even number and the first odd number in the list. If either an even or an odd number is not found, return `None`. #### Example Usage: ```python [main.nopy] print(diff_even_odd([1, 3, 5, 7, 4, 1, 6, 8])) # Output: 3 print(diff_even_odd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10])) # Output: 1 print(diff_even_odd([1, 5, 7, 9, 10])) # Output: 9 print(diff_even_odd([2, 4, 6, 8])) # Output: None print(diff_even_odd([1, 3, 5, 7])) # Output: None ``` #### Constraints: - The input list will contain at least one integer. - The function should handle cases where there are no even or odd numbers gracefully.
def diff_even_odd(numbers):
"""
Calculate the difference between the first even and first odd number in the list.
Args:
numbers (list): A list of integers.
Returns:
int or None: The difference between the first even and first odd number, or None if either is not found.
"""
# Find the first even number
first_even = None
# Find the first odd number
first_odd = None
# Iterate through the list to find the first even and odd numbers
# Placeholder for implementation
return None