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Match 'a' Followed by 'b'

Write a Python function `match_a_followed_by_b` that takes a string as input and returns `True` if the string contains an 'a' followed by one or more 'b's, and `False` otherwise. Use regular expressions to solve this problem.

#### Example Usage
```python [main.nopy]
print(match_a_followed_by_b("ab"))  # Output: True
print(match_a_followed_by_b("a"))   # Output: False
print(match_a_followed_by_b("abb")) # Output: True
print(match_a_followed_by_b("b"))   # Output: False
```

#### Constraints
- The function should be case-sensitive.
- The input string can be of any length, including empty.
import re

def match_a_followed_by_b(text):
    """
    Check if the input string contains an 'a' followed by one or more 'b's.

    Args:
        text (str): The input string to check.

    Returns:
        bool: True if the pattern is found, False otherwise.
    """
    # Define the regular expression pattern
    pattern = ''  # TODO: Add the correct regex pattern
    # Use re.search to find the pattern in the text
    return bool(re.search(pattern, text))
Intermediate regex
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