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Write a function `merge_dictionaries_three(dict1, dict2, dict3)` that takes three dictionaries as input and merges them into a single dictionary. If there are overlapping keys, the value from the dictionary that appears later in the arguments should take precedence.
#### Example Usage
```python [main.nopy]
merge_dictionaries_three({"a": 1, "b": 2}, {"b": 3, "c": 4}, {"c": 5, "d": 6})
# Output: {"a": 1, "b": 3, "c": 5, "d": 6}
merge_dictionaries_three({"x": "X"}, {"y": "Y"}, {"z": "Z"})
# Output: {"x": "X", "y": "Y", "z": "Z"}
```def merge_dictionaries_three(dict1, dict2, dict3):
"""
Merges three dictionaries into one. If keys overlap, the value from the later dictionary takes precedence.
Args:
dict1 (dict): The first dictionary.
dict2 (dict): The second dictionary.
dict3 (dict): The third dictionary.
Returns:
dict: The merged dictionary.
"""
# Placeholder for the solution
pass