Sum Series Calculation

Write a Python function `sum_series(n)` that calculates the sum of the series:

\[
S = n + (n-2) + (n-4) + \ldots
\]

The series continues until the term \( n - 2i \) becomes less than or equal to 0. For example:

- If \( n = 6 \), the series is \( 6 + 4 + 2 \), and the sum is \( 12 \).
- If \( n = 10 \), the series is \( 10 + 8 + 6 + 4 + 2 \), and the sum is \( 30 \).
- If \( n = 9 \), the series is \( 9 + 7 + 5 + 3 + 1 \), and the sum is \( 25 \).

#### Example Usage
```python [main.nopy]
print(sum_series(6))  # Output: 12
print(sum_series(10)) # Output: 30
print(sum_series(9))  # Output: 25
```

#### Constraints
- The input \( n \) will be a non-negative integer.
- If \( n \) is 0, the function should return 0.
def sum_series(n):
    """
    Calculate the sum of the series n + (n-2) + (n-4) + ... until the term is <= 0.

    Args:
    n (int): The starting number of the series.

    Returns:
    int: The sum of the series.
    """
    # Implement the function logic here
    pass
Intermediate recursion
More challenges to try
Nth Catalan Number Dictionary Depth Calculator Calculate Power Recursively Remove Uneven Elements in Nested Tuple Calculate the depth of a tree Calculate Jacobsthal Number Find the largest value in a tree Calculate the sum of all the numbers in a tree structure Find the N'th Lucas Number Harmonic Sum Calculation