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Validate Decimal Precision

Write a Python function `is_decimal` that checks whether a given string represents a decimal number with a precision of up to 2 decimal places. The function should return `True` if the string is a valid decimal number with at most two digits after the decimal point, and `False` otherwise.

#### Requirements:
- The input will be a string.
- A valid decimal number can have:
  - Only digits (e.g., `"123"` is valid).
  - A decimal point followed by up to two digits (e.g., `"123.45"` is valid).
  - No leading or trailing spaces.
  - No additional characters or multiple decimal points.

#### Examples:
```python [main.nopy]
is_decimal("123.11")  # True
is_decimal("e666.86")  # False
is_decimal("3.124587")  # False
is_decimal("1.11")  # True
is_decimal("1.1.11")  # False
```

Implement the function to meet these requirements.
def is_decimal(num: str) -> bool:
    """
    Check if the given string is a valid decimal number with up to two decimal places.

    Args:
        num (str): The string to check.

    Returns:
        bool: True if the string is a valid decimal number, False otherwise.
    """
    # Import the regular expression module
    import re

    # Define the regular expression pattern for a valid decimal number
    # Placeholder for the solution

    # Return the result of the match
    return False
Intermediate regex
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