Generate Lucid Numbers

Write a Python function `get_ludic(n)` that generates all Ludic numbers less than or equal to a given integer `n`.

A Ludic number is generated by a sieve-like process, similar to the Sieve of Eratosthenes for prime numbers. The process is as follows:

1. Start with a list of integers from 1 to `n`.
2. Remove every `k`-th number from the list, where `k` is the next number in the list after the previous step.
3. Repeat step 2 until no more numbers can be removed.

The remaining numbers in the list are Ludic numbers.

#### Example Usage
```python [main.nopy]
print(get_ludic(10))  # Output: [1, 2, 3, 5, 7]
print(get_ludic(25))  # Output: [1, 2, 3, 5, 7, 11, 13, 17, 23, 25]
print(get_ludic(45))  # Output: [1, 2, 3, 5, 7, 11, 13, 17, 23, 25, 29, 37, 41, 43]
```

#### Constraints
- `n` is a positive integer greater than or equal to 1.
def get_ludic(n):
    """
    Generate all Ludic numbers less than or equal to the given integer n.

    Args:
        n (int): The upper limit to generate Ludic numbers.

    Returns:
        list: A list of Ludic numbers up to n.
    """
    # Initialize the list of numbers from 1 to n
    # Implement the sieve process to filter Ludic numbers
    pass
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