Divisible by Own Digits

Write a Python function `divisible_by_digits(startnum, endnum)` that returns a list of numbers in the range `[startnum, endnum]` (inclusive) where each number is divisible by every non-zero digit it contains.

For example:
- The number `128` is divisible by `1`, `2`, and `8`, so it satisfies the condition.
- The number `102` does not satisfy the condition because it contains the digit `0`.

#### Example Usage
```python [main.nopy]
print(divisible_by_digits(1, 22))  # Output: [1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 15, 22]
print(divisible_by_digits(20, 25)) # Output: [22, 24]
```

#### Constraints
- `startnum` and `endnum` are positive integers with `startnum <= endnum`.
- Numbers containing the digit `0` do not satisfy the condition.
def divisible_by_digits(startnum, endnum):
    """
    Find numbers in the given range [startnum, endnum] that are divisible by every non-zero digit they contain.

    Args:
    startnum (int): The starting number of the range.
    endnum (int): The ending number of the range.

    Returns:
    list: A list of numbers satisfying the condition.
    """
    # Placeholder for the solution
    pass
Intermediate listsmath
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